Find the sample size, n, needed to estimate the mean of a normal population, μ, with σ = 9.25 and a maximum error of E = 3.2 at a 99% level of confidence.
Solution :
Given that,
standard deviation = =9.25
Margin of error = E = 3.2
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2 = 0.005
Z/2 = 2.58
sample size = n = [Z/2* / E] 2
n = ( 2.58* 9.25/ 3.2)2
n =55.61
Sample size = n =56
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