Find the indicated area under the curve of the standard normal distribution; then convert it to a percentage and fill in the blank.
About ______% of the area is between
zequals=minus−3.5
and
zequals=3.5
(or within 3.5 standard deviations of the mean).
About
nothing%
of the area is between
zequals=minus−3.5
and
zequals=3.5
(or within 3.5 standard deviations of the mean).
Solution :
For the given standard normal distribution, we will use the Z score.
To find the area between z= -3.5 and z= 3.5, we need to find P(-3.5<Z<3.5).
Now, P(-3.5<Z<3.5) = P(Z<3.5) - P(Z<-3.5)
Again P(Z<-3.5)= 1- P(Z<3.5)
From the standard normal table, we have P(Z<3.5)= 0.9998
Thus P(Z<-3.5)= 1- 0.9998= 0.0002
Hence P(-3.5<Z<3.5)= P(Z<3.5) - 0.0002
= 0.9998- 0.0002
= 0.9996
Again, converting this area into percent we get 99.96%.
Thus, about 99.96% of the area is between z= -3.5 and z= 3.5
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