A 10 sided die with sides numbered 0 through 9 is rolled 5
times. Let X be the number of zeros rolled.
(a) Find the probability that exactly 2 zeros are rolled.
(b) Find the probability that no less than 4 zeros are
rolled.
(c) Find the mean and the variance of X.
Answer)
As there are fixed number of trials and probability of each and every trial is same and independent of each other
Here we need to use the binomial formula
P(r) = ncr*(p^r)*(1-p)^n-r
Ncr = n!/(r!*(n-r)!)
N! = N*n-1*n-2*n-3*n-4*n-5........till 1
For example 5! = 5*4*3*2*1
Special case is 0! = 1
P = probability of single trial = 1/10 = 0.1
N = number of trials = 5
R = desired success
A)
P(2) = 5c2*(0.1^2)*(1-0.1)^5-2 = 0.0729
B)
P(4) + P(5)
= 0.00046
C)
Mean = n*p = 5*0.1 = 0.5
Variance = n*p*(1-p) = 5*0.1*0.9 = 0.45
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