Question

Consider random samples of size 58 drawn from population
*A* with proportion 0.78 and random samples of size 76 drawn
from population *B* with proportion 0.68 .

(a) Find the standard error of the distribution of differences
in sample proportions, p^A-p^B.

Round your answer for the standard error to three decimal
places.

standard error = Enter your answer in accordance to the question
statement

(b) Are the sample sizes large enough for the Central Limit Theorem to apply?

Yes

No

Answer #1

a)

sample #1----->A

first sample size, n1=58

proportion success of sample 1 , p̂1=0.78

sample #2----->B

second sample size, n2 = 76

proportion success of sample 1 , p̂ 2=x2/n2 = 0.68

Std error , SE = SQRT(p̂1 * (1 - p̂1)/n1 + p̂2 * (1-p̂2)/n2) =
√(0.78*(1-0.78)/58 + 0.68*(1-0.68)/76) **=
0.076(answer)**

b. Yes sample size is large enough to apply central limit theorem

-------------

please revert for doubts

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