A box contains
22
red,
22
white and
33
green balls. Two balls are drawn out of the box in succession
without replacement. What is the probability that both balls are
the same color?
Red = 22
White = 22
Green = 33
Total = 77
Case 1:
Both are Red
Probability of selecting 2 balls from 77 balls =
Probability of selecting 2 Red from 22 Red =
So,
P(2 Red) = 231/2926 = 0.0789
Case 2:
Both are White
Probability of selecting 2 balls from 77 balls =
Probability of selecting 2 White from 22 White =
So,
P(2 White) = 231/2926 = 0.0789
Case 3:
Both are Green
Probability of selecting 2 balls from 77 balls =
Probability of selecting 2 Green from 33 Green =
So,
P(2 Green) = 528/2926 = 0.1805
So,
P(same color) = 0.0789 + 0.0789 + 0.1805 = 0.3383
So,
Answer is:
0.3383
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