Question

1)

100,709
79,677
47,982
92,189
74,995
80,964
73,768
98,821
84,535
61,753
78,061
44,544
80,986
79,359
82,841
67,361
86,766
92,379
63,708
51,565
61,170
63,654
73,598
67,210
57,866
74,535
56,526
94,385
54,897
50,392
46,724
65,956
78,528
60,835
89,116

(a) Find the sample mean.

​(b) Find the sample standard deviation. The sample standard deviation is defined as is equals StartRoot StartFraction Upper Sigma left parenthesis x minus x overbar right parenthesis squared Over n minus 1 EndFraction EndRoots=Σx−x2n−1.

(c) Construct a​ 98% confidence interval for the population mean. The​ 98% confidence interval for the mean is

2)In a survey of 4063 ​adults, 734 oppose allowing transgender students to use the bathrooms of the opposite biological sex.

Construct a​ 99% confidence interval for the population proportion. Interpret the results.

A​ 99% confidence interval for the population proportion is ​(nothing​,nothing​).​

3)

1.71
1.85
1.55
1.63
1.75
1.96
1.36
1.58
1.42
2.08

The number of hours of reserve capacity of10 randomly selected automotive batteries is shown to the right.

Assume the sample is taken from a normally distributed population. Construct 90% confidence intervals for​ (a) the population variance sigmaσsquared2 and​ (b) the population standard deviation sigmaσ.

​(a) The confidence interval for the population variance is (nothing​,nothing​

​(b) The confidence interval for the population standard deviation can be found by taking the square roots of the left and right endpoints of the confidence interval for the population variance.

Answer 1