Question

A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To...

A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, a random sample of 6 employees was selected from each plant and the employees selected were given a quality awareness examination. The examination scores for these 18 employees are shown in the following table. The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that the mean examination score is the same for all three plants.

Plant 1
Atlanta
Plant 2
Dallas
Plant 3
Seattle
85 72 60
74 75 63
81 72 62
75 73 69
70 68 76
89 84 66
Sample
mean
79 74 66
Sample
variance
52.4 29.2 34.0
Sample
standard
deviation
7.24 5.40 5.83

Set up the ANOVA table for these data. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)

Source
of Variation
Sum
of Squares
Degrees
of Freedom
Mean
Square
F p-value
Treatments ? ? ? ? ?
Error ? ? ?
Total ? ?

Test for any significant difference in the mean examination score for the three plants. Use

α = 0.05.

Find the value of the test statistic. (Round your answer to two decimal places.)

_____________.

Find the p-value. (Round your answer to four decimal places.)

p-value = _________.

Homework Answers

Answer #1

Ans:

df(treatments)=3-1=2

df(error)=18-3=15

Source Sum Degrees Mean F p-value
of Variation of Squares of Freedom Square
Treatments 516 2 258 6.70 0.0084
Error 578 15 38.53
Total 1094 17

Test statistic:

F=258/38.53=6.70

p-value=FDIST(6.70,2,15)=0.0084

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