A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, a random sample of 6 employees was selected from each plant and the employees selected were given a quality awareness examination. The examination scores for these 18 employees are shown in the following table. The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that the mean examination score is the same for all three plants.
Plant 1 Atlanta 
Plant 2 Dallas 
Plant 3 Seattle 


85  72  60  
74  75  63  
81  72  62  
75  73  69  
70  68  76  
89  84  66  
Sample mean 
79  74  66 
Sample variance 
52.4  29.2  34.0 
Sample standard deviation 
7.24  5.40  5.83 
Set up the ANOVA table for these data. (Round your values for MSE and F to two decimal places, and your pvalue to four decimal places.)
Source of Variation 
Sum of Squares 
Degrees of Freedom 
Mean Square 
F  pvalue 

Treatments  ?  ?  ?  ?  ? 
Error  ?  ?  ?  
Total  ?  ? 
Test for any significant difference in the mean examination score for the three plants. Use
α = 0.05.
Find the value of the test statistic. (Round your answer to two decimal places.)
_____________.
Find the pvalue. (Round your answer to four decimal places.)
pvalue = _________.
Ans:
df(treatments)=31=2
df(error)=183=15
Source  Sum  Degrees  Mean  F  pvalue 
of Variation  of Squares  of Freedom  Square  
Treatments  516  2  258  6.70  0.0084 
Error  578  15  38.53  
Total  1094  17 
Test statistic:
F=258/38.53=6.70
pvalue=FDIST(6.70,2,15)=0.0084
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