The probability that a tennis set will go to a tiebreaker is 16%. In 220 randomly selected tennis sets, what is the mean and the standard deviation of the number of tiebreakers?
mean: 35.2; standard deviation: 5.93 |
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mean: 33; standard deviation: 5.93 |
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mean: 35.2; standard deviation: 5.44 |
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mean: 33; standard deviation: 5.44 |
Solution:
Let X be the binomial random variable with the parameter n=220 and the probability, p=0.16.That means
??X?Bin(220,0.16)??
Then,
q=1-p = 1-0.16=0.84
Mean of the binomial distribution is = np = 2200.16=35.2
Hence,Mean=35.2
Then,The Standard deviation of the Binomial distribution given as:
Standard Deviation,???=? npq ??
???=? 220×0.16×0.84 ??
=??? 29.568 ?? =5.44
Hence, Standard deviation of the binomial random variable X is 5.44
Therefore, Mean=35.2 and Standard Deviation=5.44
Option (c) is correct.
Cheers!!
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