Two technicians regularly make repairs when breakdowns occur on an automated production line. The first technician, who service 40% of the breakdowns, has 5% chance of making incomplete repair. The second technician, who services 60% of the breakdowns, has a 3% chance of making an incomplete repair. Given that there is a problem with the production line due to an incomplete repair, what is the probability that this initial repair was made by the first technician?
Given data:
1st technician service s1= 40%=0.4
chance of making incomplete repair of 1st technician i1=0.05
Probability for 1st technician make incomplete service P(1)= i1*s1=0.05*0.4 =0.02
2nd technician service s2= 60%=0.6
chance of making incomplete repair of 2nd technician i2=0.03
Probability for 2nd technician make incomplete service P(2)= i2*s2=0.03*0.6 =0.018
Probability for problem with the production line due to an incomplete repair P(1st & 2nd) =P(1)+P(2)= 0.018+0.02 = 0.038
Probability that problem in production line due to an incomplete repair that this initial repair was made by the first technician =P(1 | 1st & 2nd)
P(1 | 1st & 2nd) = P(1)/P(1st & 2nd) = 0.02/0.38
=0.5263
Probability that problem in production line due to an incomplete repair that this initial repair was made by the first technician is 0.5263
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