Choose one of the words in the following sentence uniformly at random and then choose one of the letters of that word, again uniformly at random:
SOME DOGS ARE BROWN
Given that the chosen letter is R, what is the probability that the chosen word was BROWN?
There are 4 words and these are equally likely so probability of selecting any word is 1/4. That is
P(SOME) = P(DOGS) =P(ARE)=P(BROWN) = 1/4
Now word SOME has no letter R so
P(R | SOME) = 0
Word DOGS has no letter R so
P(DOGS) = 0
Word ARE has one letter R out of three so
P(ARE) = 1/3
Word BROWN has one letter R out of five so
P(BROWN) = 1/5
By the Bayes' theorem the probability that the chosen word was BROWN given that chosen letter is R will be
Answer: 0.375
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