Use the Poisson Distribution Formula to find the
indicated probability.
For a certain type of fabric, the average number
of defects in each square foot of fabric is 1.8. Find the
probability that a randomly selected square foot of the fabric will
contain at least two defects.
Round your answer to four decimal places.
Hint: The answer is the complement of the probability that there is at most 1 defect
The distribution is:
1.8 | mean rate of occurrence | |
cumulative | ||
X | P(X) | probability |
0 | 0.1653 | 0.1653 |
1 | 0.2975 | 0.4628 |
2 | 0.2678 | 0.7306 |
3 | 0.1607 | 0.8913 |
4 | 0.0723 | 0.9636 |
5 | 0.0260 | 0.9896 |
6 | 0.0078 | 0.9974 |
7 | 0.0020 | 0.9994 |
8 | 0.0005 | 0.9999 |
9 | 0.0001 | 1.0000 |
10 | 0.0000 | 1.0000 |
11 | 0.0000 | 1.0000 |
12 | 0.0000 | 1.0000 |
13 | 0.0000 | 1.0000 |
1.00000 |
Required probability = 0.5372
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