Consider data transmission between two computers in different
geographical locations. Data is transmitted in ‘blocks’, that is,
in fixed-length sequences of digits. Suppose that the transmission
may be routed over any one of three different routes, the selection
being made automatically by a route selector according to existing
traffic conditions, every time transmission of a block is
initiated. Transmission takes place over the three routes various
fractions of the time, as follows:
Route A: 60% of the time
Route B: 30% of the time
Route C: 10% of the time
Transmission errors can occur that render a block completely
useless. The probability of a block experiencing such an error
depends on the route. It is
0.001 when route A is used
0.002 when route B is used
0.003 when route C is used.
What is the probability that an error, when it does occur, arises
on route C?
This question can be solved by Bayes Theorem
Let E represent the event of a transmission error.
We are given:
P(A) = 0.60
P(B) = 0.30
P(C) = 0.10
P(E/A)= 0.001
P(E/B) = 0.002
P(E/C) = 0.003
We have to calculate the probability P(C/E)
We know by the definition of conditional probability:
Using Bayes theorem:
The required probability is 20%.
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