Question

The heights of American adult males are normally distributed
with a mean of 177 cm and a standard deviation of 7.4 cm. Use the
Empirical Rule to find the range of heights that contain
approximately

(a) 68% of the data

cm -- cm

(b) 95% of the data

cm -- cm

(c) 99.7% of the data

cm -- cm

Answer #1

The heights of adult males are known to be normally distributed
with a mean of 70 inches and a standard deviation of 2 inches.
a) Find the probability that a randomly selected adult male will
be taller than 75 inches?
(b) If three adult males are picked at random, find the
probability that at least one of the males is taller than 75
inches.

A large study of the heights of 920 adult men found that the
mean height was 71 inches tall. The standard deviation was 7
inches. If the distribution of data was normal, what is the
probability that a randomly selected male from the study was
between 64 and 92 inches tall? Use the 68-95-99.7 rule (sometimes
called the Empirical rule or the Standard Deviation rule). For
example, enter 0.68, NOT 68 or 68%.

The distribution of adult men’s heights is approximately
normally distributed with mean 175.0 cm and standard deviation 6.40
cm. State answers rounded to one place of decimal. [4] a)
Approximately what percentage of men are taller than 183 cm? b)
What height is such that approximately 90% of men are taller than
this height?

he heights of American men are normally distributed with a mean
of 71.3 inches and a standard deviation of 3.7 inches. According to
the empirical rule, what percentage of American men are:
(a) Between 63.9 and 78.7 inches tall?
Answer: %
(b) Under 75 inches tall?
Answer: %
(c) Over 73.779 inches tall?
Answer: %

The heights of all adult American women are normally
distributed with a mean of 63.8 inches and a standard deviation of
6 inches. Give the standard (z) score and approximate
percentile (from the tables) for women with each of the following
heights:
64 inches
62 inches
60.5 inches

The heights of adult men in America are normally distributed,
with a mean of 69.1 inches and a standard deviation of 2.67 inches.
The heights of adult women in America are also normally
distributed, but with a mean of 64.8 inches and a standard
deviation of 2.56 inches.
a) If a man is 6 feet 3 inches tall, what is his z-score (to two
decimal places)?
z =
b) If a woman is 5 feet 11 inches tall, what is...

Suppose baseball batting averages were normally distributed with
mean 250 and standard deviation 15. Using the approximate
EMPIRICAL RULE about what percentage of players
would have averages BETWEEN 220 and 235 ?
Question 6 options:
About 99.7%
About 97.5%
About 95%
About 84%
About 68%
About 47.5%
About 34%
About 20%
About 16%
About 13.5%
About 2.5%
Less than 1%
No Answer within 1% Given
Question 7 (1 point)
Suppose men's heights were normally distributed with mean 180
cm. and...

A set of exam scores is normally distributed with a mean = 80
and standard deviation = 10.
Use the Empirical Rule to complete the following
sentences.
68% of the scores are between _____ and ______.
95% of the scores are between ______ and _______.
99.7% of the scores are between _______ and ________.
Get help: Video

The heights of adult men in America are normally distributed,
with a mean of 69.7 inches and a standard deviation of 2.65 inches.
The heights of adult women in America are also normally
distributed, but with a mean of 64.1 inches and a standard
deviation of 2.57 inches.
a) If a man is 6 feet 3 inches tall, what is his z-score (to two
decimal places)?
b) If a woman is 5 feet 11 inches tall, what is her z-score...

Suppose a normally distributed set of data has a mean of 193 and
a standard deviation of 13. Use the 68-95-99.7 Rule to determine
the percent of scores in the data set expected to be below a score
of 219. Give your answer as a percent and includeas many decimal
places as the 68-95-99.7 rule dictates. (For example, enter 99.7
instead of 0.997.)

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 1 minute ago

asked 7 minutes ago

asked 10 minutes ago

asked 10 minutes ago

asked 10 minutes ago

asked 11 minutes ago

asked 11 minutes ago

asked 12 minutes ago

asked 23 minutes ago

asked 30 minutes ago

asked 32 minutes ago

asked 39 minutes ago