A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 122.8-cm and a standard
deviation of 0.6-cm. For shipment, 6 steel rods are bundled
Find the probability that the average length of a randomly selected bundle of steel rods is less than 122.7-cm.
P(M < 122.7-cm) =
Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Given that ,
mean = = 122.8
standard deviation = = 0.6
n = 6
m = 122.8
m = / n = 0.6 / 6=0.2449
P(M < 122.7) = P[(M - m ) / m < (122.7 -122.8) /0.2449 ]
= P(z < -0.408)
Using z table
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