The CEO of a company would like to determine whether advertising increases sales. So the null hypothesis tested is H0: μd ≤ 0. The CEO hires you to conduct the analysis for the period 2018 to 2019. Using a Matched sample design yields the following result:
t-Test: Paired Two Sample for Means |
||
2019 |
2018 |
|
Mean |
191.8 |
172.05 |
Variance |
2030.574359 |
2878.664103 |
Observations |
40 |
40 |
Pearson Correlation |
0.821186783 |
|
Hypothesized Mean Difference |
0 |
|
df |
39 |
|
t Stat |
4.077479845 |
|
P(T<=t) one-tail |
0.000108536 |
|
t Critical one-tail |
1.684875122 |
|
P(T<=t) two-tail |
0.000217072 |
|
t Critical two-tail |
2.02269092 |
Note: alpha = 0.05.
From the given information the null and alternative hypothesis is
H0: μd ≤ 0.
H0: μd > 0.
The test is one tailed
a) here we will use p-value =0.0002 to make the decision because test is one tailed
b) since p value is less than 0.05 so we will reject the null hypothesis.
c) we have sufficient evidence to accept the claim that a dvertising increases sales.
d) yes we will recommend that this company continues to use this advertisement because we have proved that advertisement increases sales
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