The CEO of a company would like to determine whether advertising increases sales. So the null hypothesis tested is H_{0}: μ_{d} ≤ 0. The CEO hires you to conduct the analysis for the period 2018 to 2019. Using a Matched sample design yields the following result:
tTest: Paired Two Sample for Means 

2019 
2018 

Mean 
191.8 
172.05 
Variance 
2030.574359 
2878.664103 
Observations 
40 
40 
Pearson Correlation 
0.821186783 

Hypothesized Mean Difference 
0 

df 
39 

t Stat 
4.077479845 

P(T<=t) onetail 
0.000108536 

t Critical onetail 
1.684875122 

P(T<=t) twotail 
0.000217072 

t Critical twotail 
2.02269092 
Note: alpha = 0.05.
From the given information the null and alternative hypothesis is
H0: μd ≤ 0.
H0: μd > 0.
The test is one tailed
a) here we will use pvalue =0.0002 to make the decision because test is one tailed
b) since p value is less than 0.05 so we will reject the null hypothesis.
c) we have sufficient evidence to accept the claim that a dvertising increases sales.
d) yes we will recommend that this company continues to use this advertisement because we have proved that advertisement increases sales
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