7. The test scores of one hundred students reveal a mean of 70 and a standard deviation of 5. According to Chebyshev:
**Please show work
7. a) Chebyshev theorem states that the proportion of the distribution within "k" standard deviation of the mean is at-least 1 - (1/k2)
Now, we need to find out the proportion of students that will score between 60 and 80,
60 = u - s*k = 70 - 5*k
80 = u + s*k = 70 + 5*k
k = 2
Proportion of students = 1 - (1/4) = 3/4 = 0.75
Hence, atleast 75% of the students will score between 60 and 80.
b) We need to find out the proportion of students that will score between 63 and 77,
63 = u - s*k = 70 - 5*k
77 = u + s*k = 70 + 5*k
k = 1.40
Proportion of students = 1 - (1/1.96) = 0.49
Hence, atleast 49% of the students will score between 63 and 77.
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