Question

The final marks for the Wednesday class in Statistics 101 are ready to be posted. The...

The final marks for the Wednesday class in Statistics 101 are ready to be posted. The class average is 80%, with a standard deviation of 5. The distribution of grades is approximately bell-shaped. (Round the final answers to 2 decimal places.) a. What percentage of the grades are above 85? Percentage of grades % b. What percentage of the grades are below 75? Percentage of grades % c. What percentage of the grades are between 70 and 85? Percentage of grades % d. What percentage of the grades are between 70 and 90? Percentage of grades % e. What percentage of the grades are between 70 and 95? Percentage of grades % f. What percentage of the grades are less than 65 or more than 85? Percentage of grades %

Statistics

Homework Answers

Answer #1

a)

for normal distribution z score =(X-μ)/σx
here mean=       μ= 80
std deviation   =σ= 5

percentage of the grades are above 85 :

probability =P(X>85)=P(Z>(85-80)/5)=P(Z>1)=1-P(Z<1)=1-0.8413=0.1587~ 15.87 %

b) percentage of the grades are below 75 :

probability =P(X<75)=(Z<(75-80)/5)=P(Z<-1)=0.1587~ 15.87%

c)

probability =P(70<X<85)=P((70-80)/5)<Z<(85-80)/5)=P(-2<Z<1)=0.8413-0.0228=0.8185~ 81.85%

d)

probability =P(70<X<90)=P((70-80)/5)<Z<(90-80)/5)=P(-2<Z<2)=0.9772-0.0228=0.9544~ 95.44 %

e)

probability =P(70<X<95)=P((70-80)/5)<Z<(95-80)/5)=P(-2<Z<3)=0.9987-0.0228=0.9759~ 97.59%

f)

probability =1-P(65<X<95)=1-P((65-80)/5)<Z<(95-80)/5)=1-P(-3<Z<3)=1-(0.9987-0.0013)=0.0026~ 0.26 %
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