A fertilizer distributor sells fertilizer in 10 kg bags. A customer feels that the distributor sells underweight bags. To support his hunch, he purchases 8 bags of fertilizer. They have an average weight of 9.65 kg with standard deviation 0.7 kg. Does the customer have a case against the distributor? Test using α = 0.05.
Solution :
= 10
= 9.65
s = 0.7
n = 8
This is the left tailed test .
The null and alternative hypothesis is
H0 : = 10
Ha : < 10
Test statistic = t
= ( - ) / s / n
= (9.65 - 10) / 0.7 / 8
= -1.41
P (t< -1.41 ) = 0.1007
P-value = 0.1007
= 0.05
0.01007 > 0.05
Do not reject the null hypothesis .
There is insufficient evidence to suggest that
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