Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a sample of size 199 with 52 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places.
C.I. =
Solution :
Given that,
Point estimate = sample proportion = = x / n = 52 / 199 = 0.261
1 - = 1 - 0.261 = 0.739
Z/2 = 2.326
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 2.326 * (((0.261 * 0.739) /199 )
= 0.072
A 98% confidence interval for population proportion p is ,
- E < p < + E
0.261 - 0.072 < p < 0.261 + 0.072
0.189 < p < 0.333
C.I = 0.189 , 0.333
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