There are three cups that are turned upside down. Beneath two of the cups is a piece of chocolate; the last cup has nothing underneath it. You are free to choose which cup you want to turn over. What is the probability that you will first choose a cup with chocolate then, on the next choice, choose the second cup with chocolate? (After the first cup is turned over, it is not replaced.)
initially there are 3 cups with 2 having chocolate, probability of picking cup with chocolate :
P(chocolate) = 2/3
now there are 2 cups remaining with one having chocolate, probability of picking cup with chocolate :
P(chocolate) = 1/2
Therefore,
P(1st cup has chocolate AND 2nd cup has chocolate) = P(1st cup has chocolate)*P(2nd cup has chocolate) = 2/3 * 1/2
P(1st cup has chocolate AND 2nd cup has chocolate) = 2/6 = 1/3
P(1st cup has chocolate AND 2nd cup has chocolate) = 1/3
P.S. (please upvote if you find the answer satisfactory)
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