5)
A zoologist weights 19 newborn African elephants born in captivity. The mean weight of the sample is 183.5 lbs with a standard deviation of 5.3 lbs.
a) Find a 99% confidence interval for the true weight of newborn African elephants born in captivity.
b) Provide the right endpoint of the interval as your answer.
Round your answer to 1 decimal place.
Solution :
Given that,
= 183.5
s = 5.3
n = 19
Degrees of freedom = df = n - 1 = 9 - 1 = 8
a ) At 99% confidence level the t is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
t /2,df = t0.005,8 =2.878
Margin of error = E = t/2,df * (s /n)
= 2.878 * (5.3 / 9)
= 3.5
Margin of error = 3.5
b ) The 99% confidence interval estimate of the population mean is,
+ E
183.5 + 3.5
Right endpoint =187.0
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