Question

A quality inspector learns that 2 of the 20 incoming pallets from a supplier contained the wrong part number. Five of these pallets have been placed in production. What is the probability that at least 1 of the pallets containing the wrong part has been placed into production? Please answer question using the Hypergeometric Distribution. Thank You.

Answer 1

the probability that at least 1 of the pallets containing the wrong part has been placed into production = 1 - P(No wrong part)

N = Population Size = 20

S = Number of Successes in the population = 2

F = Number of Failures in the population = 18

n = Sample Size = 5

s = Number of Successes in the Sample = 0

f = Number of Failures in the population = 5

Using Hypergeometric Distribution, we get:

P(X =0) = h(x=5; n=5, S=2, F = 18) = 0.5526

So,

the probability that at least 1 of the pallets containing the wrong part has been placed into production = 1 - P(No wrong part)

= 1 -0.5526 = 0.4474

So,

Answer is:

0.4474