Question

Assume that the probability of a being born with Genetic Condition B is p = 53/60. A study looks at a random sample of 336 volunteers.

(a) Find the most likely number of the 336 volunteers to have Genetic Condition

(b) Let X represent the number of volunteers (out of 336) who have Genetic Condition B. Find the standard deviation for the probability distribution of X

Answer 1

It is given that  the probability of a being born with Genetic Condition B is p = 53/60

n = sample size = 336

a) So that the most likely number of the 336 volunteers to have Genetic Condition = n*p = 336*(53/60) = 296.8 = 297

b) Let X = the number of volunteers (out of 336) who have Genetic Condition B.

So, X follows binomial distribution with mean n*p and standard deviation() is as