Question

Assume that the probability of a being born with Genetic Condition B is p = 53/60. A study looks at a random sample of 336 volunteers.

(a) Find the most likely number of the 336 volunteers to have Genetic Condition

(b) Let X represent the number of volunteers (out of 336) who have Genetic Condition B. Find the standard deviation for the probability distribution of X

Answer #1

It is given that the probability of a being born with Genetic Condition B is p = 53/60

n = sample size = 336

a) So that the most likely number of the 336 volunteers to have
Genetic Condition = n*p = 336*(53/60) = 296.8 =
**297**

**b)** Let X = the number of volunteers (out of
336) who have Genetic Condition B.

So, X follows binomial distribution with mean n*p and standard deviation() is as

question25
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