Question

A random sample of n = 25 is obtained from a population with variance 2 ,...

A random sample of n = 25 is obtained from a population with variance 2 , and the sample mean is computed to be  = 70. Consider the null hypothesis H0 :  = 80 against H1 :  < 80 and compute the p-value when 2 = 600.

Homework Answers

Answer #1

Given,

n = 25

X_bar = 70

2 =600

Hypothesis :

H0: =80

H1: < 80

First calculate test statistic value

= 2 = 600 = 24.49

t= (x_bar - ​​​​​​) /(/n)

= (70-80)/(24.49/25)

t = - 2.042

Calculate df

Df =n-1 = 25-1 = 24

P value for t test statistic with 24 degree of freedom is 0.0262.

P value = 0.0262

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A random sample n=30 is obtained from a population with unknown variance. The sample variance s2...
A random sample n=30 is obtained from a population with unknown variance. The sample variance s2 = 100 and the sample mean is computed to be 85. Test the hypothesis at α = 0.05 that the population mean equals 80 against the alternative that it is more than 80. The null hypothesis Ho: µ = 80 versus the alternative H1: Ho: µ > 80. Calculate the test statistic from your sample mean. Then calculate the p-value for this test using...
To test H0: σ=70 versus H1: σ<70​, a random sample of size n equals 25 is...
To test H0: σ=70 versus H1: σ<70​, a random sample of size n equals 25 is obtained from a population that is known to be normally distributed. ​(a) If the sample standard deviation is determined to be s equals = 46.5​, compute the test statistic. ​(b) If the researcher decides to test this hypothesis at α=0.05 level of​ significance, use technology to determine the​ P-value. ​(c) Will the researcher reject the null​ hypothesis? What is the P-Value?
From a random sample from normal population, we observed sample mean=84.5 and sample standard deviation=11.2, n...
From a random sample from normal population, we observed sample mean=84.5 and sample standard deviation=11.2, n = 16, H0: μ = 80, Ha: μ < 80. State your conclusion about H0 at significance level 0.01. Question 2 options: Test statistic: t = 1.61. P-value = 0.9356. Reject the null hypothesis. There is sufficient evidence to conclude that the mean is less than 80. The evidence against the null hypothesis is very strong. Test statistic: t = 1.61. P-value = 0.0644....
A random sample of size n=55 is obtained from a population with a standard deviation of...
A random sample of size n=55 is obtained from a population with a standard deviation of σ=17.2, and the sample mean is computed to be x=78.5. Compute the 95% confidence interval. Compute the 90% confidence interval. SHOW WORK
A sample of 5 observations from the population indicated that sample variance s12 is 441. A...
A sample of 5 observations from the population indicated that sample variance s12 is 441. A second sample of 10 observations from the same population indicated that sample variance s22 is 196. Conduct the following test of hypothesis using a 0.05 significance level. H0: σ12 = σ22 H1: σ12 < σ22 You should use the tables in the book for obtaining the F values. For full marks your answer should be accurate to at least two decimal places. a) State...
A simple random sample of size n=15 is drawn from a population that is normally distributed....
A simple random sample of size n=15 is drawn from a population that is normally distributed. The sample mean is found to be bar over x=19.5 and the sample standard deviation is found to be s=6.3. Determine if the population mean is different from 25 at the alpha=.01 level of significance. A) Determine the null and alternative hypotheses H0: ___ ____ 25 H1: ____ ____ 25 B) Calculate the p value C) State conclusion. Reject or not reject? Is there...
A parent population has a true mean equal to 25. A random sample of n=16 is...
A parent population has a true mean equal to 25. A random sample of n=16 is taken and the estimated standard deviation is 6.0 What is the value of the standard error of the mean in this instance? What percentage of sample means would be expected to lie within the interval 23.5 to 26.5? What is the t-value (in absolute value) associated with a 95% symmetric confidence interval? What is the lower bound of the 95% confidence interval? T/F A...
A sample of 8 observations from the population indicated that sample variance s12 is 784. A...
A sample of 8 observations from the population indicated that sample variance s12 is 784. A second sample of 8 observations from the same population indicated that sample variance s22 is 144. Conduct the following test of hypothesis using a 0.05 significance level.   H0: σ12 = σ22   H1: σ12 < σ22 You should use the tables in the book for obtaining the F values. For full marks your answer should be accurate to at least two decimal places. a) State...
A sample of 6 observations from the population indicated that sample variance s12 is 529. A...
A sample of 6 observations from the population indicated that sample variance s12 is 529. A second sample of 5 observations from the same population indicated that sample variance s22 is 256. Conduct the following test of hypothesis using a 0.1 significance level.   H0: σ12 = σ22   H1: σ12 ≠ σ22 You should use the tables in the book for obtaining the F values. For full marks your answer should be accurate to at least two decimal places. a) State...
A random sample of n = 500 books is selected from a library and the number...
A random sample of n = 500 books is selected from a library and the number of words in the title of each book is recorded. The sample mean number of words in the title is 6.2 words. The population variance is 40 words^2 . Please show how to do each one using R and Rstudio. a) (2 points) Compute the z-statistic for testing the null hypothesis H0 : µ = 7. b) (3 points) Perform a level ? =...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT