Question

the weight of each chicken should be close as possible to 2 kg

a random sample of 26 chickens prepared over the past few weeks had a mean weight of 1.60 kg with a standard deviation of 0.50kg.

if i use a two tailed test and a significance level of 0.05 should i accept or reject that the average weight of the chicken is the require 2.00 kg

should it be a Z or t-test used

Answer 1

Solution :

= 1.60

= 2.0

s = 0.50

n = 26

This is the two tailed test .

The null and alternative hypothesis is

H₀ :   = 1.60

H_a :    1.60

Test statistic = t

= ( - ) / s / n

= (2 - 1.60) / 0.50 / 26

= 4.079

p(Z > 4.079) = 1-P (Z < 4.079 ) = 0.0004

P-value = 0.0004

= 0.05  

0.0004 < 0.05

Reject the null hypothesis .

There is sufficient evidence to suggest that