Question

Consider the One-Way ANOVA table (some values are intentionally left blank) for the amount of food (kidney, shrimp, chicken liver, salmon and beef) consumed by 50 randomly assigned cats (10 per group) in a 10-minute time interval.

H₀: All the 5 population means are equal   H₁: At least one population mean is different.

Population: 1 = Kidney, 2 = Shrimp, 3 = Chicken Liver, 4 = Salmon, 5 = Beef.

ANOVA
Source of Variation	SS	df	MS	F	P-value	F crit
Between Groups	----	-----	0.91474	--------	9.15E-10	2.578739
Within Groups	1.98	-----	0.043966
Total	5.63745	49

What is the sum of squares 'Between Groups' value (SSA) or factor sum of squares?

  

Select one:

a. 2.9987

b. 3.66

c. 5.7654

d. 1.98

Consider the One-Way ANOVA table (some values are intentionally left blank) for the amount of food (kidney, shrimp, chicken liver, salmon and beef) consumed by 50 randomly assigned cats (10 per group) in a 10-minute time interval.

H₀:All the 5 population means equal           H₁: At least one population mean is different.

Population: 1 = Kidney, 2 = Shrimp, 3 = Chicken Liver, 4 = Salmon, 5 = Beef.

ANOVA
Source of Variation	SS	df	MS	F	P-value	F crit
Between Groups	------	-----	0.91474	--------	9.15E-10	2.578739
Within Groups	1.97849	-----	0.043966
Total	5.63745	49

What are the 'Between Groups' or factor degrees of freedom and what is the F_STAT value?

Select one:

a. 45, 20.81

b. 49, 22.12

c. 45, 32.12

d. 4, 20.81

Consider the One-Way ANOVA table (some values are intentionally left blank) for the amount of food (kidney, shrimp, chicken liver, salmon and beef) consumed by 50 randomly assigned cats (10 per group) in a 10-minute time interval.

H₀:All the 5 population means equal           H₁: At least one population mean is different.

Population: 1 = Kidney, 2 = Shrimp, 3 = Chicken Liver, 4 = Salmon, 5 = Beef.

ANOVA
Source of Variation	SS	df	MS	F	P-value	F crit
Between Groups	------	-----	0.91474	--------	9.15E-10	2.578739
Within Groups	1.97849	-----	0.043966
Total	5.63745	49

Given that all the 5 groups (populations) have 10 observations each (sample sizes); the critical range value according to Tukey-Kramer procedure is 0.2513 at α = 0.05 ; and the absolute difference between means for kidney and shrimp groups is 0.22 then we can say that the pair wise difference among means of kidney and shrimp populations is-----

Select one:

a. significant at α = 0.01

b. insufficient information

c. significant at α = 0.05

d. not significant at α = 0.05

Answer 1