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A coin is tossed three times. An outcome is represented by a string of the sort HTT (meaning a head on the first toss, followed by two tails). The 8 outcomes are listed in the table below. Note that each outcome has the same probability.
For each of the three events in the table, check the outcome(s) that are contained in the event. Then, in the last column, enter the probability of the event.

Event B: More heads than tails 

Event C: Alternating head and tail (with either coming first) 

The set of possible outcomes while tossing a coin three times are
S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT},
Therefore, total number of possible outcomes = 8
We know that the probability of an event, say event A, is defined as
The probabilities of the events mentioned in the question are calculated using the above formula and is tabluted below:
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