Assume that adults have IQ scores that are normally distributed with a mean of 101 and a standard deviation 24. Find the first quartile Upper Q 1, which is the IQ score separating the bottom 25% from the top 75%.
Solution:-
Given that,
mean = = 101
standard deviation = = 24
Using standard normal table,
The z dist'n First quartile is,
P(Z < z) = 25%
= P(Z < z) = 0.25
= P(Z < -0.6745 ) = 0.25
z = -0.6745
Using z-score formula,
x = z * +
x = -0.67 * 24 + 101
x = 84.92
First quartile =Q1 = 84.92
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