According to a survey of American households, the probability that the residents own two cars if annual household income is over $75,000 is 73%. Of the households surveyed, 60% had incomes over $75,000 and 72% had two cars.
The probability that the residents of a household own two cars and have an income over $75,000 a year is..... round 3 decimal places
Solution:
Suppose that
Event A : residents own two cars
Event B : had incomes over $75,000
Now , from given
P(A) = 72% = 0.72
P(B) = 60% = 0.60
Also given , P(A | B) = 73% = 0.73
But from the definition of the conditional probability ,
P(A | B) = P(A B)/P(B)
0.73 = P(A B)/0.60
P(A B) = 0.73 * 0.60 = 0.438
Answer :
The probability that the residents of a household own two cars and have an income over $75,000 a year is 0.438
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