A class survey in a large class for first-year college students asked, "About how many minutes do you study on a typical weeknight?" The mean response of the 285 students was x⎯⎯⎯x¯ = 132 minutes. Suppose that we know that the study time follows a Normal distribution with standard deviation σσ = 65 minutes in the population of all first-year students at this university.
Use the survey result to give a 95% confidence interval for the mean study time of all first-year students.
Solution :
Given that,
Z/2 = 1.96
Margin of error = E = Z/2* ( /n)
= 1.96 * (65 / 285)
= 7.55
At 95% confidence interval estimate of the population mean is,
- E < < + E
132 - 7.55 < < 132 + 7.55
124.45 < < 139.55
(124.45 , 139.55)
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