A bank has kept records of the checking balances of its customers and determined that the average daily balance of its customers is $300 with a standard deviation of $48, and is a normally distributed population. A random sample of 144 checking accounts is selected.
a) What is the probability that the sample mean will be at least $306.60
Solution :
Given that ,
mean = = 300
standard deviation = = 48
n = 144
= 300 and
= / n = 48 / 144 = 48 / 12 = 4
(a)
P( ) = 1 - P( 306.60)
= 1 - P(( - ) / < (306.60 - 300) / 4)
= 1 - P(z < 1.65)
= 1 - 0.9505
= 0.0495
P( > 306.60) = 0.0495
Probability = 0.0495
Get Answers For Free
Most questions answered within 1 hours.