a random sample of 13 students were asked how long it took them to complete a certain exam. The mean length of time was 122.1 minutes what the standard deviation of 66.6 minutes. Final lower bound of 90% confidence interval for the true mean length of time it would take for all students to complete the exam . Round to one decimal place
Solution :
Given that,
Point estimate = sample mean = = 122.1
sample standard deviation = s = 66.6
sample size = n = 13
Degrees of freedom = df = n - 1 = 13 - 1 = 12
At 90% confidence level the t is ,
t = 1 - 90% = 1 - 0.90 = 0.1
t,df = t0.1,12 = 1.356
Margin of error = E = t,df * (s /n)
= 1.356 * (66.6 / 13)
= 25.0
At 90% lower confidence level is
- E
122.1 - 25.0
97.1
lower bound is 97.1
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