A manufacturer knows that their items have a normally
distributed lifespan, with a mean of 3.6 years,
and standard deviation of 0.7 years. If you randomly purchase one
item, what is the probability it will
last longer than 4 years?
Answer:
=3.6 , =0.7, n=1
P(x > 4) =?
Z = 0.571429
Z=0.57
P(x > 4) = 1 - P(Z 0.57)
now, look to normal z table to get P(Z 0.57)
we get,
P(Z 0.57) = 0.7157
now, P(x > 4) = 1 - P(Z 0.57)
P(x > 4) = 1- 0.7157
P(x > 4) = 0.2843
probability of item will last longer than 4 years = 0.2843
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