A publisher reports that 75% of their readers own a particular make of car. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 310 found that 70%
of the readers owned a particular make of car. Determine the P-value of the test statistic. Round your answer to four decimal places.
Solution:
Let p be the population proportion.
Claim to be tested is " p = 75% vs p 75% "
n = 310
Let be the sample proportion.
= 70% = .70
Use = 0.01
Null and alternative hypothesis are
H0 : p = 0.75
H1 : p 0.75
2)The test statistic z is
z =
= (0.70- 0.75)/[0.75*(1 - 0.75)/310]
= -2.03
p value
sign in H1 indicates that the test is "Two Tailed"
p value = P(Z < -2.03) + P(Z > +2.03)
= 0.0212+ 0.0212
= 0.0424
p value = 0.0424
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