The average weight of an airline passenger’s suitcases is 45 pounds with a standard deviation of 2 pounds. If 16% of the suitcases are overweight, find the maximum weight allowed by the airline. Assume the variable is bell – shaped distributed. Hint: Sketch and label a normal model to help answer the question.
Solution :
Given that,
mean = = 45
standard deviation = = 2
Using standard normal table ,
P(Z > z) = 16%
1 - P(Z < z) = 0.16
P(Z < z) = 1 - 0.16
P(Z < 0.99) = 0.84
z = 0.99
Using z-score formula,
x = z * +
x = 0.99 * 2 + 45 = 46.98
maximum weight = 46.98
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