Let X be a random variable with possible values {−2, 0, 2} and such that P(X = 0) = 0.2. Compute E(X^2 ).
Let X be a random variable with possible values {−2, 0, 2} and such that P(X = 0) = 0.2.
Let's consider P(X=-2)=p
Therefore, P(X=2)=0.8-p, Since sum of all probabilities should be 1.
Hence,
## Taking 4 common from both the ters.
Thus
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