scientists want to estimate the mean weight of mice after they have been fed a special diet period from previous studies that is known that the weight is normally distributed with standard deviation 6 grams. How many mice must be weighed so that 95% confidence interval will have a margin error of 0.5 grams ? Right only an integer as your answer
Solution :
Given that,
Population standard deviation = = 6
Margin of error = E = 0.5
At 95% confidence level the z is,
= 1 - 95%
= 1 - 0.95 = 0.05
/2 = 0.025
Z/2 = 1.96
sample size = n = [Z/2* / E] 2
n = [1.96 * 6 / 0.5]2
n = 553.19
Sample size = n = 554
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