Suppose at a particular traffic light junction, the traffic is
green 60 % of the time, red
30 % of the time and yellow 10 % of the time. Given that a car
approaches this traffic
light junction once each day. Let X denotes the number of days that
pass up to and
including the first time the car encounters a red light. Assume
that each day represents
an independent trial.
(i) Apply a suitable model and compute the probability P(X =
3).
(ii) Compute the probability P(X ≤ 4).
Let X denotes the number of days that pass up to and including the first time the car encounters a red light and the trials are independent
The model used can be the geometric, where p = 30% = 0.3
and q = 1 - p= 1 - 0.3 = 0.7
(i) Apply a suitable model and compute the probability P(X = 3)
Using geometric P[ X = x+1 ] = q^x*p
P(X = 3) = 0.7^2*0.3
P(X = 3) = 0.147
(ii) Compute the probability P(X ≤ 4)
P[ X <= 4 ] = P[ X = 1 ] + P[ X = 2 ] + P[ X = 3 ] + P[ X = 4 ]
P[ X <= 4 ] = 0.7^0*0.3 + 0.7^1*0.3 + 0.7^2*0.3 + 0.7^3*0.3
P[ X <= 4 ] = 0.3 + 0.21 + 0.147 + 0.1029
P[ X <= 4 ] = 0.7599
P[ X <= 4 ] = 0.76
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