The weights of a certain dog breed are approximately normally
distributed with a mean of 53 pounds, and a standard deviation of
5.9 pounds. Answer the following questions. Write your answers in
percent form. Round your answers to the nearest tenth of a
percent.
a) Find the percentage of dogs of this breed that weigh less than
53 pounds. %
b) Find the percentage of dogs of this breed that weigh less than
49 pounds. %
c) Find the percentage of dogs of this breed that weigh more than
49 pounds. %
Solution :
Given that,
mean = = 53
standard deviation = = 5.9
P(X<53 ) = P[(X- ) / < (53-53) /5.9 ]
= P(z < 0)
Using z table
= 0.500
=50%
B.
P(X<49 ) = P[(X- ) / < (49-53) /5.9 ]
= P(z < -0.68)
Using z table
= 0.2483
=24.83%
C.
P(X>49 ) =1 - P[(X- ) / < (49-53) /5.9 ]
= P(z < -0.68)
Using z table
= 1 - 0.2483
=0.7517
=75.17%
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