Question

Construct the 98 % confidence interval for the difference −μ1μ2 when =x1475.12 ,   =x2321.34 ,   =s143.48...

Construct the

98

%

confidence interval for the difference

−μ1μ2

when

=x1475.12

,  

=x2321.34

,  

=s143.48

,  

=s221.60

,  

=n112

, and

=n215

. Use tables to find the critical value and round the answers to at least two decimal places.

A

98

%

confidence interval for the difference in the population means is

<<−μ1μ2

.

Homework Answers

Answer #1

please like ??

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Construct a 98​% confidence interval to estimate the population mean when x overbar =64 and s​...
Construct a 98​% confidence interval to estimate the population mean when x overbar =64 and s​ =12.8 for the sample sizes below. ​a) n= 21 ​b) n=41 ​c) 56 ​ a) The 98​% confidence interval for the population mean when n=21 is from a lower limit of _______to an upper limit of ________. ​(Round to two decimal places as​ needed.) b) The 98​% confidence interval for the population mean when n=41 is from a lower limit of _______to an upper...
Suppose a researcher wishes to construct a 99% ?-confidence interval for the difference of two independent...
Suppose a researcher wishes to construct a 99% ?-confidence interval for the difference of two independent means with unknown population standard deviations. His sample sizes are ?1=7 and ?2=10, and his calculated Satterthwaite approximate degrees of freedom are 12.513. What is the positive ?‑critical value for this confidence interval, rounded to 3 decimal places?
Suppose a researcher wishes to construct a 90% ?-confidence interval for the difference of two independent...
Suppose a researcher wishes to construct a 90% ?-confidence interval for the difference of two independent means with unknown population standard deviations. His sample sizes are ?1=8 and ?2=12, and his calculated Satterthwaite approximate degrees of freedom are 15.756. What is the positive ?‑critical value for this confidence interval, rounded to 3 decimal places? ? =
Given that n= 120 and X = 9, construct a 98% confidence interval estimate for the...
Given that n= 120 and X = 9, construct a 98% confidence interval estimate for the population proportion (π). What is the sample proportion (compute)? What is the standard error of the proportion (compute)? What are the critical values? From what distribution? What is the confidence interval (compute)? State the interval values to at least 3 decimal places. If an expert asserted that the population proportion was 0.10, at a 98% level of confidence, would the data gathered in this...
1) Find the critical value t (a/2) needed to construct a confidence interval of the given...
1) Find the critical value t (a/2) needed to construct a confidence interval of the given level with the given sample size. Round the answers to three decimal places a) 98% sample size 11 critical value- b) for level 95% and sample size 25 critical value- c)for level 99% and sample size 14 2) a sample of size n equals 45 has a sample mean X equals 56.9 and sample standard deviation s equals 9.4. construct a 99% confidence interval...
Construct a 98% confidence interval for the population mean. Given: n = 15; X̄ = 104.8;...
Construct a 98% confidence interval for the population mean. Given: n = 15; X̄ = 104.8; s = 3. Assume the population is normal. Round answer to 3 decimal places.
Consider the following data from two independent samples with equal population variances. Construct a 98​% confidence...
Consider the following data from two independent samples with equal population variances. Construct a 98​% confidence interval to estimate the difference in population means. Assume the population variances are equal and that the populations are normally distributed. x1=37.9 x2=32.9 s1=8.7 s2=9.2 n1=15 n2=16 Click here to see the t-distribution table page 1, Click here to see the t-distribution table, page 2 The 98​% confidence interval is ​what two numbers. ​(Round to two decimal places as​ needed.)
Recall the method used to obtain a confidence interval for the difference between two population means...
Recall the method used to obtain a confidence interval for the difference between two population means for matched samples. (a) The following data are from matched samples taken from two populations. Compute the difference value for each element. (Use Population 1 − Population 2.) Element Population Difference 1 2 1 11 8 2 7 8 3 9 6 4 12 7 5 13 10 6 15 15 7 15 14 (b) Compute d. (c) Compute the standard deviation  sd.  (Round your answer...
n1   13   n2   9 x1bar   141   x2bar   161 s1   13   s2   12 Use this data to...
n1   13   n2   9 x1bar   141   x2bar   161 s1   13   s2   12 Use this data to find the 98%98% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed. Copy Data Step 1 of 3: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places. Step 2 of 3: Find the standard error of the...
Construct an 80% confidence interval for the population standard deviation if a sample of size 7...
Construct an 80% confidence interval for the population standard deviation if a sample of size 7 has standard deviation s=10.5. Round the answers to at least two decimal places.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT