A statistics instructor randomly selected four bags of oranges, each bag labeled 10 pounds, and weighed the bags. They weighed 10.3, 10.2, 10.3, and 10.4 pounds.
Assume that the distribution of weights is Normal. Find a 95% confidence interval for the mean weight of all bags of oranges. Use technology for your calculations.
a. Choose the correct interpretation of the confidence interval. Is the answer A,B,C or D and the 2 numbers.
A.We are 95% confident that the sample mean is between Answer ____ and ____.
B.We are 95% confident the population mean is between Answer ____ and ____.
C.There is a 95% chance that all intervals will be between Answer ___ and ___
D. The requirements for constructing a confidence interval are not satisfied.
(Type integers or decimals rounded to the nearest thousandth as needed. Use ascending order.)
sample mean, xbar = 10.3
sample standard deviation, s = 0.0817
sample size, n = 4
degrees of freedom, df = n - 1 = 3
Given CI level is 95%, hence α = 1 - 0.95 = 0.05
α/2 = 0.05/2 = 0.025, tc = t(α/2, df) = 3.182
ME = tc * s/sqrt(n)
ME = 3.182 * 0.0817/sqrt(4)
ME = 0.13
CI = (xbar - tc * s/sqrt(n) , xbar + tc * s/sqrt(n))
CI = (10.3 - 3.182 * 0.0817/sqrt(4) , 10.3 + 3.182 *
0.0817/sqrt(4))
CI = (10.17 , 10.43)
A.We are 95% confident that the popultion mean is between Answer
10.170 and 10.430
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