The weight of a tool manufactured by a tool maker follows a normal distribution with a mean of 8kg and a standard deviation of 1.5kg.
For quality control, the Production manager was rejecting any manufactured tool weighing under 6.5 kg. Calculate the approximate percentage of rejected tools.
A. |
10% |
|
B. |
16% |
|
C. |
20% |
|
D. |
25% |
|
E. |
13% |
Solution:
Given, X follows Normal distribution with,
= 8
= 1.5
Now ,
P(X < 6.5)
= P[(X - )/ < (6.5 - )/]
= P[Z < (6.5 - 8)/1.5]
= P[Z < -1.00]
= 0.1587 ... ( use z table)
= 15.87%
= 16% nearly
Answer : 16%
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