Question

Find the margin of error for the given values of c, s, and n.

c=0.80, s=2.3, n=10

Answer #1

Solution :

Given that,

s =2.3

n =10

Degrees of freedom = df = n - 1 = 10- 1 = 9

At 80% confidence level the t is ,

= 1 - 80% = 1 - 0.80 = 0.20

/ 2= 0.20 / 2 = 0.10

t
/2,df = t0.10,9 = **1.383** ( using student t
table)

Margin of error = E = t/2,df * (s /n)

= **1.383** * ( 2.3/
10)

= 1.0059

Margin of error = E =1.0059

Find the margin of error for the given values of c, s, and
n.
c=0.80,
s=3.4,
n=14

Find the margin of error for the given values of c, s, and
n.
cequals=0.8080,
sequals=66,
nequals=2626
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The margin of error is?
(Round to one decimal place as needed.)

Find the margin of error for the given values of c, sigma, and
n. cequals0.95, sigmaequals3.3, nequals100

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n. cequals0.95, sigmaequals3.9, nequals100

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n.
c=0.90, σ=3.3, n=81.
Eequals= _ (Round to three decimal places as needed.)

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sigmaσ,
and n.
cequals=0.950.95,
sigmaσequals=2.82.8,
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Find the margin of error for the given confidence level and
values of x and n. x = 80, n = 146, confidence level 99%

Find the margin of error for the given confidence level and
values of x and n. x=79, n=187, 98% confidence level

Find the Margin of Error for each problem:
1) c = .95; n =
30; s = 3.5 Margin of Error=
2) c = .85; n =
18; s = 0.49 Margin of Error=
3) c = .95; n =
12; s = 12.6 Margin of Error=
4) c = .99; n =
26; s = 18.9 Margin of Error=
Round answers to three decimal places.

Find the value of E, the margin of error, for c equals 0.99,
n equals 10 and s equals 3.6.

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