Question

Find the margin of error for the given values of c, s, and n.

c=0.80, s=2.3, n=10

Answer #1

Solution :

Given that,

s =2.3

n =10

Degrees of freedom = df = n - 1 = 10- 1 = 9

At 80% confidence level the t is ,

= 1 - 80% = 1 - 0.80 = 0.20

/ 2= 0.20 / 2 = 0.10

t
/2,df = t0.10,9 = **1.383** ( using student t
table)

Margin of error = E = t/2,df * (s /n)

= **1.383** * ( 2.3/
10)

= 1.0059

Margin of error = E =1.0059

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The margin of error is?
(Round to one decimal place as needed.)

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