Question

Find the margin of error for the given values of​ c, s, and n.

c=0.80​, s=2.3​, n=10

Answer 1

Solution :

Given that,

s =2.3

n =10

Degrees of freedom = df = n - 1 = 10- 1 = 9

At 80% confidence level the t is ,

= 1 - 80% = 1 - 0.80 = 0.20

  / 2= 0.20 / 2 = 0.10

t /2,df = t0.10,9 = 1.383 ( using student t table)

Margin of error = E = t/2,df * (s /n)

= 1.383 * ( 2.3/ 10)

= 1.0059

Margin of error = E =1.0059