Question

74% of freshmen entering public high schools in 2006 graduated with their class in 2010. a random sample of 81 freshmen is selected. Find the probability that the proportion of students who graduated is greater than 0.743. write only a number as your answer. round to 4 decimal places.

Answer 1

Solution

Given that,

=  [p( 1 - p ) / n] = [(0.74 * 0.26) / 81 ] = 0.0487

P( > 0.743) = 1 - P( < 0.743)

= 1 - P(( - ) / < (0.743 - 0.74) / 0.0487)

= 1 - P(z < 0.06)

= 1 - 0.5239

= 0.4761

Probability = 0.4761