A box contains 3 nickels and 4 quarters. two coins are selected at random from the seven coins at the random variable X is a value of the two coins. Give the probability distribution for x.
3 nickels and 4 quarters
total n = 7
two coins are selected at random from the seven coins at the random variable X is a value of the two coins
X = 2 nickels
P( X = 2 nickels ) = 3C2/7C2
P( X = 2 nickels ) = 3/(7*6/2)
P( X = 2 nickels ) = 6/(7*6)
P( X = 2 nickels ) = 1/7
X = 2 quarters
P( X = 2 quarters ) = 4C2/7C2
P( X = 2 quarters ) = (4*3/2)/(7*6/2)
P( X = 2 quarters ) = 12/42
P( X = 2 quarters ) = 2/7
X = 1 nickel and 1 quarter
P( X = 1 nickel and 1 quarter ) = 4C1*3C1/7C2
P( X = 1 nickel and 1 quarter ) = 4*3/(7*6/2)
P( X = 1 nickel and 1 quarter ) = 12/21
P( X = 1 nickel and 1 quarter ) = 4/7
probability distribution for x
X | 2 nickels | 1 nickel 1 quarter | 2 quarters | Total |
P(X) | 1/7 | 4/7 | 2/7 | 1 |
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