Question
Continine Levels (nmol/l) Subject After 12 Hours After 24 Hours 1 2 3 4 5 6...
|
Continine Levels (nmol/l) |
||
|
Subject |
After 12 Hours |
After 24 Hours |
|
1 2 3 4 5 6 7 |
73 58 67 93 33 18 147 |
24 27 49 59 00 11 43 |
Let mu 12 represent the population mean continine level 12 hours after smoking the cigarette and mu 24 the mean continine level 24 hours after smoking. It is believed that mu 24 must be lower than mu 12.
1. test H0: µ12 = µ24 vs. HA: µ12 ≠ µ24 at the 5% level.
2. construct a 95% CI for µ12 − µ24
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