A study shows that the lengths of the careers of professional football players are nearly normally distributed, with a mean of 6.2 years and a standard deviation of 1.9 years.
(a) What percent of professional football players have a career of more than 9 years? (Round your answer to one decimal place.) %
(b) If a professional football player is chosen at random, what is the probability that the player will have a career of between 3 and 4 years? (Round your answer to three decimal places.)
Solution :
Given that ,
mean = = 6.2
standard deviation = = 1.9
P(x >9 ) = 1 - P(x< 9)
= 1 - P[(x -) / < (9 -6.2) /1.9 ]
= 1 - P(z <1.47 )
Using z table
= 1 - 0.9292
= 0.0708
answer=7.1%
(B)
P(3< x <4 ) = P[(3 -6.2) /1.9 < (x - ) / < (4 -6.2) / 1.9)]
= P(-1.68 < Z < -1.16)
= P(Z < -1.16) - P(Z < -1.68)
Using z table
= 0.1230-0.0465
probability= 0.077
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