Solution :
degrees of freedom = n - 1 = 199 - 1 = 198
t/2,df = t0.025,198 = 1.972
Margin of error = E = t/2,df * (s /n)
= 1.972 * ( 7.6 / 199)
Margin of error = E = 1.1
The 95% confidence interval estimate of the population mean is,
- E < < + E
31.3 - 1.1 < < 31.3 + 1.1
( 30.2 hg < < 32.4 hg )
Yes, because the confidence interval limits are not similar
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