In a test of two population means - μ1μ1 versus μ2μ2 - with
unknown variances σ21σ12 and σ22σ22, two independent samples of
n1=8n1=8 and n2=10n2=10 were taken. The data is given below. Both
populations are normally distributed.
Sample From Population 1: 11, 7, 14, 14, 19, 16, 16, 16 ;
Sample From Population 2: 16, 15, 19, 16, 16, 14, 19, 20, 20,
18
You wish to test the hypothesis that both populations have the
same variance. Choose the correct statistical hypotheses.
A. H0:σ21≠σ22HA:σ21=σ22H0:σ12≠σ22HA:σ12=σ22
B. H0:σ21=σ22HA:σ21≠σ22H0:σ12=σ22HA:σ12≠σ22
C.
H0:σ21=σ22HA:σ21<σ22H0:σ12=σ22HA:σ12<σ22
D. H0:S21=S22HA:S21≠S22H0:S12=S22HA:S12≠S22
E.
H0:σ21=σ22HA:σ21>σ22H0:σ12=σ22HA:σ12>σ22
(b) Determine the value of the test statistic for this test. Use at
least two decimals in your answer.
Test Statistic =
(c) Determine the P-value for this test, to at least three decimal
places.
Part a
The null and alternative hypotheses for this test are given as below:
B. H0: σ12 = σ22 versus HA: σ12 ≠ σ22
[...because claim is given as the both populations have same variance.]
Part b
The test statistic value is given as below:
F = S1^2/S2^2
From given data, we have
S1^2 = 13.55357143
S2^2 = 4.677777778
F = 13.55357143 / 4.677777778
F = 2.89743807
Test statistic = F = 2.89743807
Part c
We have
F = 2.89743807
n1 = 8
n2 = 10
df1 = n1 – 1 = 8 – 1 = 7
df2 = n2 – 1 = 10 – 1 = 9
So, P-value by using F-table or excel is given as below:
P-value = 0.1400
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