Question

In a random sample of n = 750 families owning television sets in a city of...

In a random sample of n = 750 families owning television sets in a city of Hamilton Canada, it was found that x = 340 subscribed to HBO. Find the 95% confidence interval for the mean of all such containers assuming an approximate normal distribution.

What statistical table will be used?

What is the tabular value?

What is the lower confidence limit?

What is the upper confidence limit?

Homework Answers

Answer #1

Z distribution table

table value = 1.96

Lower confidence limit = 0.418

Upper confidence limit = 0.489

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a random sample of 1000 families owning Netflix accounts in the charlottesville, it is found...
In a random sample of 1000 families owning Netflix accounts in the charlottesville, it is found that 688 watched the Spanish TV series “Money Heist’’. Find a 95% confidence interval for the actual proportion of families with Netflix accounts in charlottesville that watched “Money Heist”
A sociologist is studying the prevalence of crime in one major city. In a sample of...
A sociologist is studying the prevalence of crime in one major city. In a sample of 150 randomly selected residents, 45 say that they have been victimized by a criminal. Based on this sample, construct a 95% confidence interval for the proportion of all residents in this city who have been victimized by a criminal. Then complete the table below.Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a...
A sample of n = 16 is to be taken from a distribution that can reasonably...
A sample of n = 16 is to be taken from a distribution that can reasonably be assumed to be Normal with a standard deviation σ of 100. The sample mean comes out to be 110. 1. The standard error of the mean, that is, the standard deviation of the sample mean, is σx¯ = σ/√ n. What is its numerical value? 2. The 97.5 percentile, 1.96, of the standard Normal distribution is used for a 95% confi- dence interval....
In a random sample of 830 adults in the U.S.A., it was found that 84 of...
In a random sample of 830 adults in the U.S.A., it was found that 84 of those had a pinworm infestation. You want to find the 95% confidence interval for the proportion of all U.S. adults with pinworm. (a) What is the point estimate for the proportion of all U.S. adults with pinworm? Round your answer to 3 decimal places. (b) Construct the 95% confidence interval for the proportion of all U.S. adults with pinworm. Round your answers to 3...
In a random sample of 830 adults in the U.S.A., it was found that 84 of...
In a random sample of 830 adults in the U.S.A., it was found that 84 of those had a pinworm infestation. You want to find the 95% confidence interval for the proportion of all U.S. adults with pinworm. (a) What is the point estimate for the proportion of all U.S. adults with pinworm? Round your answer to 3 decimal places. (b) What is the critical value of z (denoted zα/2) for a 95% confidence interval? Use the value from the...
Pinworm: In a random sample of 790 adults in the U.S.A., it was found that 80...
Pinworm: In a random sample of 790 adults in the U.S.A., it was found that 80 of those had a pinworm infestation. You want to find the 95% confidence interval for the proportion of all U.S. adults with pinworm. (a) What is the point estimate for the proportion of all U.S. adults with pinworm? Round your answer to 3 decimal places. (b) What is the critical value of z (denoted zα/2) for a 95% confidence interval? Use the value from...
A random sample of 200 individuals working in a large city indicated that 58 are dissatisfied...
A random sample of 200 individuals working in a large city indicated that 58 are dissatisfied with their working conditions. Based upon this, compute a 90% confidence interval for the proportion of all individuals in this city who are dissatisfied with their working conditions. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.) What is the lower limit of the...
Pinworm: In a random sample of 780 adults in the U.S.A., it was found that 76...
Pinworm: In a random sample of 780 adults in the U.S.A., it was found that 76 of those had a pinworm infestation. You want to find the 95% confidence interval for the proportion of all U.S. adults with pinworm. (a) What is the point estimate for the proportion of all U.S. adults with pinworm? Round your answer to 3 decimal places. (b) What is the critical value of z (denoted zα/2) for a 95% confidence interval? Use the value from...
A simple random sample of size n is drawn. The sample​ mean, x overbarx​, is found...
A simple random sample of size n is drawn. The sample​ mean, x overbarx​, is found to be 18.4, and the sample standard​ deviation, s, is found to be 4.9 Construct a 95​% confidence interval about muμ if the sample​ size, n, is 35. find lower and upper bounds. Construct a 99​% confidence interval about muμ if the sample​ size, n, is 35 what is the lower and upper bounds?
A simple random sample of size n is drawn. The sample​ mean, x overbar​, is found...
A simple random sample of size n is drawn. The sample​ mean, x overbar​, is found to be 17.6​, and the sample standard​ deviation, s, is found to be 4.1. LOADING... Click the icon to view the table of areas under the​ t-distribution. ​(a) Construct a 95​% confidence interval about mu if the sample​ size, n, is 35. Lower​ bound: nothing​; Upper​ bound: nothing ​(Use ascending order. Round to two decimal places as​ needed.) ​(b) Construct a 95​% confidence interval...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT